Join 84,000+ Looksmaxxing Members!

Register a FREE account today to become a member. Once signed in, you'll be able to participate on this site by adding your own topics and posts, as well as connect with other members through your own private inbox.

  • DISCLAIMER: DO NOT ATTEMPT TREATMENT WITHOUT LICENCED MEDICAL CONSULTATION AND SUPERVISION

    This is a public discussion forum. The owners, staff, and users of this website ARE NOT engaged in rendering professional services to the individual reader. DO NOT use the content of this website as an alternative to personal examination and advice from licenced healthcare providers. DO NOT begin, delay, or discontinue treatments and/or exercises without licenced medical supervision. Learn more

proof of my iq

Deleted Member 78476

Well-known member
Reputable ★★★
Established ★★★
Joined
Jul 25, 2025
Messages
17,965
Solutions
1
Online time
29d 13h
Reputation
52,436
I dont have the time to take the test because my mind works overtime but this is the only valid source you need
Screenshot 2025-09-20 at 15.59.55.png

high
 
Yeah it's in thermodynamics (k=A.e^-EA/RT)
yes
Which statement about the Arrhenius equation is correct?

A plot of ln k against T gives a straight line.

When T is very large ln k almost equals ln A.

Ea is the gradient of a plot of ln k against 1/T.

A plot of k against 1/T gives a straight line.
 
yes
Which statement about the Arrhenius equation is correct?

A plot of ln k against T gives a straight line.

When T is very large ln k almost equals ln A.

Ea is the gradient of a plot of ln k against 1/T.

A plot of k against 1/T gives a straight line.
explain your answer
 
yes
Which statement about the Arrhenius equation is correct?

A plot of ln k against T gives a straight line.

When T is very large ln k almost equals ln A.

Ea is the gradient of a plot of ln k against 1/T.

A plot of k against 1/T gives a straight line.
Second one because at high temperatures ea/Rt equals 0 so
 
yes
Which statement about the Arrhenius equation is correct?

A plot of ln k against T gives a straight line.

When T is very large ln k almost equals ln A.

Ea is the gradient of a plot of ln k against 1/T.

A plot of k against 1/T gives a straight line.
I lowk forgor this but it’s easy I assure you
 

Users who are viewing this thread

Back
Top